|
Home | Libraries | People | FAQ | More |
boost::proto::make::impl
// In header: <boost/proto/transform/make.hpp> template<typename Expr, typename State, typename Data> struct impl : proto::transform_impl< Expr, State, Data > { // types typedef see-below result_type; // public member functions result_type operator()(typename impl::expr_param, typename impl::state_param, typename impl::data_param) const; };
impl
public
typestypedef see-below result_type;
proto::make<T>::impl<Expr, State, Data>::result_type is
computed as follows:
If T is an ObjectTransform of the form
Object(A0,...An),
then let O be the return type
Object. Otherwise, let O
be T. The result_type typedef is
then computed as follows:
If proto::is_transform<O>::value is
true, then let the result type be
boost::result_of<proto::when<_, O>(Expr, State, Data)>::type
.
Note that a substitution took place.
O is a template like
proto::noinvoke<S<X0,...Xn> >,
then the result type is calculated as follows:
For each i in
[0,n], let
Xi'
be
boost::result_of<proto::make<Xi>(Expr, State, Data)>::type
(which evaluates this procedure recursively). Note that a substitution took place. (In this case,
Proto merely assumes that a substitution took place for the sake of compile-time efficiency. There
would be no reason to use proto::noinvoke<>
otherwise.)
The result type is
S<X0',...Xn'>
.
O is a template like
S<X0,...Xn>,
then the result type is calculated as follows:
For each i in
[0,n], let
Xi'
be
boost::result_of<proto::make<Xi>(Expr, State, Data)>::type
(which evaluates this procedure recursively). Note whether any substitutions took place during
this operation.
If any substitutions took place in the above step and
S<X0',...Xn'>
has a nested
type typedef, the result type is
S<X0',...Xn'>::type
.
Otherwise, the result type is
S<X0',...Xn'>
.
O, and note that no
substitution took place.
Note that proto::when<> is implemented
in terms of proto::call<>
and proto::make<>, so the
above procedure is evaluated recursively.
impl public member functionsresult_type operator()(typename impl::expr_param expr, typename impl::state_param state, typename impl::data_param data) const;
behaves as follows:
proto::make<T>::impl<Expr,State,Data>::operator()
If T is of the form
O(A0,...An), then:
If
is proto::is_aggregate<result_type>::value
true, then construct
and return an object that as follows:
result_type that = {
proto::when<_, A0>()(expr, state, data),
...
proto::when<_, An>()(expr, state, data)
};
Otherwise, construct
and return an object that as follows:
result_type that(proto::when<_, A0>()(expr, state, data), ...proto::when<_, An>()(expr, state, data) );
Otherwise, construct
and return an object that as follows:
result_type that = result_type();